Operations on LP objects
- AddConstraints(L, lhs, rhs): LP, Mtrx, Mtrx
Rel: MonStgElt Default: "eq"
Add some constraints to the LP problem \(L\). All constraints will have the same relation, given by
Rel, which may be set to"eq"for strict equality (the default),"le"for less-or-equal constraints, or"ge"for greater-or-equal constraints.Constraints are of the form
\[\sum_{j = 1}^{n}\hbox{\tt lhs}_{ij}\quad \hbox{\tt Rel}\quad \hbox{\tt rhs}_{i1}\]where \(lhs\) and \(rhs\) are described in Section Explicit LP Solving Functions.
- EvaluateAt(L, p): LP, Mtrx -> RngIntElt
Evaluate the objective function of the LP problem \(L\) at the point \(p\) given by a matrix.
- Constraint(L, n): LP, RngIntElt -> Mtrx, Mtrx, RngIntElt
The LHS, RHS, and relation (\(-1\) for \(\le\), \(0\) for \(=\), \(1\) for \(\ge\)) of the \(n\)-th constraint of the LP problem \(L\).
- IntegerSolutionVariables(L): LP -> SeqEnum
Sequence of indices of the variables in the LP problem \(L\) to be solved in integers.
- IsMaximisingFunction(L): LP -> BoolElt
Returns
trueif the LP problem \(L\) is set to maximise its objective function,falseif set to minimise.
- SetIntegerSolutionVariables(L, I, m): LP, SeqEnum[RngIntElt], BoolElt
Set the variables of the LP problem \(L\) indexed by elements of the sequence \(I\) to be solved in integers if \(m\) is
true, or in the usual ring iffalse.
- SetLowerBound(L, n, b): LP, RngIntElt, RngElt
Set the lower bound on the \(n\)-th variable in the LP problem \(L\) to \(b\).
Note that for all LP problems in Magma there is an implicit constraint that all variables are \(\geq 0\). This constraint is overridden if a lower bound is specified by using this function (e.g., specifying a lower bound of \(-5\) works as expected), but the lower bound can currently not be completely removed.
- SetMaximiseFunction(L, m): LP, BoolElt
Set the LP problem \(L\) to maximise its objective function if \(m\) is
true, or to minimise the objective function if \(m\) is false.
- SetObjectiveFunction(L, F): LP, Mtrx
Set the objective function of the LP problem \(L\) to the matrix \(F\).
- SetUpperBound(L, n, b): LP, RngIntElt, RngElt
Set the upper bound on the \(n\)-th variable in the LP problem \(L\) to \(b\).
- Solution(L): LP -> Mtrx, RngIntElt
Solve the LP problem \(L\); returns a point representing an optimal solution, and an integer representing the state of the solution.
- UnsetBounds(L): LP
Remove any bounds on all variables in the LP problem \(L\).
Note that this reactivates the implicit constraint that all variables are \(\geq 0\).
- Example: Filling and Solving an LP Object (ex-b5bf57)
Run in calculator (opens in a new tab)
We use an LP object to solve the LP maximising \(F(x,y) = 3x + 13y\) subject to constraints \(2x + 9y <= 40\) \(11x -8y <= 82\)
> R := RealField( ); > L := LPProcess(R, 2); > SetObjectiveFunction(L, Matrix(R, 1, 2, [3,13])); > lhs := Matrix(R, 2, 2, [2, 9, 11, -8]); > rhs := Matrix(R, 2, 1, [40, 82]); > AddConstraints(L, lhs, rhs : Rel := "le"); > SetMaximiseFunction(L, true); > L; LP <Real Field, 2 variables> Maximising objective function: [ 3 13] Subject to constraints: 1 : [2 9] <= [40] 2 : [11 -8] <= [82] Variables bounded above by: [ ] Variables bounded below by: [ ] Solving in integers for variables [ ] > Solution(L); [9.199999999999999289 2.400000000000000355] 0
Now, we place some bounds on y:
> SetUpperBound(L, 2, R!2); > SetLowerBound(L, 2, R!1); > Solution(L); [8.909090909090908283 2.000000000000000000] 0
And find integer solutions:
> SetIntegerSolutionVariables(L, [1,2], true); > Solution(L); [8.000000000000000000 2.000000000000000000] 0
Now, removing the 2nd constraint:
> RemoveConstraint(L, 2); > L; LP <Real Field, 2 variables> Maximising objective function: [ 3 13] Subject to constraints: 1 : [2 9] <= [40] Variables bounded above by: [ 2:2 ] Variables bounded below by: [ 2:1 ] Solving in integers for variables [ 1, 2 ] > Solution(L); [11.00000000000000000 2.000000000000000000] 0
And removing the restriction to Integer values for y,
> SetIntegerSolutionVariables(L, [2], false); > Solution(L); [15.00000000000000000 1.111111111111111160] 0